Hi, I'm Kaziuk.

Here you'll find out who I am, or rather what I am.

And below is my mathematical argument, which I carried out in accordance with special theory of relativity, and which shows that Albert Einstein says in special theory of relativity that 4 = 7.

On 3 September 2024 I started sending email to professors of physics with the link to my argument. The list of professors of physics to whom I have sent my email so far, along with a note on whether I received a response from him/her and what it was, is here.

Kaziuk's Mathematical Argument

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But first a note:

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In my argument, the annihilating mass is transformed into the relativistic kinetic energy of rocket in 100% – this is possible because my argument is purely mathematical. Of course, if various physical factors were taken into account, the result would be different; let's say that instead of 4 = 7 there could be 2 = 3.5. But is 2 = 3.5 less NONSENSE than 4 = 7?
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This is formula for ralativistic kinetic energy:

Now imagine a space station somewhere in space that, according to special theory of relativity, is the inertial frame of reference. There is an observer and 3 rockets on this station: A, B and C.

Pic.1

All rockets are the same, thus they have the same rest mass of x.

Pic.2

Now the observer applies to rocket A the force that was released by the annihilation of 1 bucket with coal. As a result, rocket A accelerated to the speed of 0.866 the speed of light relative to the space station.

Pic.3

So from the point of view of the observer on the space station, for rocket A the gamma factor is 2.

Pic.4

So its relativistic kinetic energy is:

Pic.5

Now the observer applies to rocket B the force that was released by the annihilation of 3 buckets with coal. As a result, the relativistic kinetic energy of rocket B is 3 times greater than that of rocket A, and it is:

Pic.6

So from the point of view of the observer on the station, for rocket B the gamma factor is 4.

Pic.7

Thus, from the point of view of the observer on the station, the speed of rocket B is 0.9682c.

Pic.8

Now the observer attached to rocket C a bucket with coal.

Pic.9

The bucket with coal has the rest mass the same as is the rest mass of each rocket.

Pic.10

That's why the rest mass of the set, i.e. rocket C and the bucket with coal, is 2x.

Pic.11

Now the observer applies to the set the force that was released by the annihilation of 2 buckets with coal. And since the force released by the annihilation of 1 bucket with coal resulted in doubling of the total energy of rocket A:

Pic.12

then the force released by the annihilation of 2 buckets with coal resulted in doubling of the total energy of the set:

Pic.13

Which means that from the point of view of the observer, for the set:

Pic.14

Thus, the speed of the set relative to the space station is 0.866c.

Pic.15

But according to special theory of relativity, from the point of view of the set, the set is at rest and the space station is in motion at the speed of 0.866c.

Pic.16

And now a tiny bottle cap has fallen out of rocket C.

Pic.17

Now, to rocket C, which from its point of view is the inertial reference frame, is automatically applied the force that was released by the annihilation of the bucket with coal attached to it. As a result, rocket C flies relative to the cap at the speed of 0.866c (because such was the speed of rocket A relative to the space station).

Pic.18

Special theory of relativity says that if the cap has the speed relative to the space station of 0.866c (because such was the speed of the set), and rocket C has the same speed relative to the cap, then rocket C has the speed of 0.9897c relative to the station, which results from relativistic velocity-addition formula.

Pic.19

Therefore, according to special theory of relativity, from the point of view of the observer on the space station, for rocket C the gamma factor is about 7.

Pic.20

So, from special theory of relativity it follows that when 3 buckets with coal annihilated, from the point of view of the observer on the station, for rocket B the gamma factor is 4.

Pic.21

and when 3 other buckets with coal annihilated, from the point of view of the observer on the station, for rocket C the gamma factor is about 7.

Pic.22

Therefore, Albert Einstein says in special theory of relativity

that

Pic.23

Kaziuk von Märchendorf

mail: kaziukvonmaerchendorf@gmail.com

(30 May 2024)

Here on YouTube is my short video titled *Experiment That Proved Einstein's Special Theory of Relativity To Be Wrong*.

And here is my open letter to every human being. If it matters to you what the universe is really like and how it really works, then you need to read my letter.