Hi, I'm Kaziuk.
Here is my text titled "A Simple Way to Debunk Einstein's Special Theory of Relativity."
And below is my mathematical argument which I carried out in accordance with the law of conservation of energy and which I have called Kaziuk's Sequence.
Kaziuk's Sequence consists of 3 sentences, where each subsequent sentence is a continuation of the previous one.
For demonstrating* that Kaziuk's Sequence is wrong**, is the prize from me:
$1,000,000
If, like human professors of physics, you take Einstein's special theory of relativity for granted,
"We now take Einstein's special theory of relativity for granted." – text posted by human professors of physics on the website of University of Pittsburgh.
then present Kaziuk's Sequence to a human professor of physics – he/she will prove it wrong, and then you'll share the prize.
Kaziuk's Sequence
Polska wersja
First, introduction:
Somewhere in intergalactic space there's a huge launch platform with the rest mass of 1,000,000 * 1,000,000 kg.
On the platform there is a rocket with an astronaut, a jar of fuel and probe A; the rest mass of the rocket with its entire inventory is 1,000,000 kg, so its rest energy is:
E0 = 1,000,000 * mc2 = 1,000,000;
; instead of * mc2 is my invention – it's intended to make Kaziuk's Sequence more transparent by removing what is immutable and therefore negligible.
The rest mass of the fuel in the jar on board the rocket is 1 kg, so its rest energy is:
E0 = 1 * mc2 = 1;
The rest mass of probe A on board the rocket is 1 kg, so its rest energy is:
E0 = 1 * mc2 = 1;
There is another identical probe B on the platform, so its rest mass is also 1 kg, so its rest energy is also:
E0 = 1 * mc2 = 1;
There are also 1,000,000 jars of fuel stored on the platform + 1 jar of fuel, the same as the one on board the rocket.
First sentence:
Then, the force of 1x was applied to probe B by annihilating 1 jar of fuel stored on the platform, and the force of 1,000,000x was applied to the rocket with its entire inventory by annihilating 1,000,000 jars of fuel stored on the platform; so to every 1 kg of mass was applied the force of 1x; as a result, probe B and the rocket with its entire inventory reached the same speed.
Addition to the first sentence:
The application of force to probe B and to the rocket occurred under the same conditions and circumstances, and both propulsion systems operate on the same principle – so all of this is negligible in Kaziuk's Sequence; especially since Kaziuk's Sequence is not a physics textbook, but mathematical argument.
Second sentence:
But first, a note:
From speed, you can calculate the increase in mass, and from the increase in mass, you can calculate the speed.
In Kaziuk's Sequence, the speed of probe B is 0.866c, because this speed occurs when the body's mass increases by factor of 1 + 1 = 2.
And in Kaziuk's Sequence, the increase in probe B's mass is doubled, because in Kaziuk's Sequence, all the rest energy of 1 kg of fuel is transferred into the kinetic energy of probe B which has the rest mass of 1 kg – this is for clarity.
And it doesn't matter what the actual kinetic energy of probe B with the rest mass of 1 kg would be as a result of the annihilation of 1 kg of fuel, and therefore it doesn't matter what the actual increase in probe B's mass and its speed would be, because in every situation, the result of Kaziuk's Sequence would be different from what results from special theory of relativity – which I demonstrated later, assuming a situation where the increase in probe B's mass would not be 1 + 1 = 2-fold, but, for example, 1 + 0.5 = 1.5-fold.
And that's precisely what the Kaziuk Sequence is about – not about its final result, but about the fact that whatever the result is, it would never be the same as what results from special theory of relativity in an analogous situation.
And anyone who claims otherwise is asked not to babble, but to present a SPECIFIC value for the speed of probe B with a SPECIFIC increase in its mass, and then to compare the final result of Kaziuk's Sequence in this modified version with what results from special theory of relativity, and to make sure it is one and the same – and for that is the prize of $1,000,000.
Now the rocket and probe B are flying relative to the platform at the same constant speed of 0.866c, so the Lorentz factor
for the rocket and probe B is:
γ = 2
and therefore, the kinetic energy
of the rocket with its entire inventory is:
Ek = 1,000,000; * (2 – 1) = 1,000,000;
and probe B is:
Ek = 1; * (2 – 1) = 1;
Addition to the second sentence:
When the fuel in 1 jar stored on the platform – whose rest mass was 1 kg and rest energy was 1; – annihilated, this released energy was transferred into the kinetic energy of probe B; as a result, probe B – whose rest mass is 1 kg and rest energy is 1; – now, when in motion relative to the platform, its total energy is 1; [rest] + 1; [kinetic] = 2;, which is twice as large, so the Lorentz factor for probe B is 2, and consequently the speed of probe B relative to the platform is 0.866c, because at this speed the Lorentz factor is 2.
And the same process applies to the rocket with its entire inventory, so the Lorentz factor for the rocket with its entire inventory is also 2, and its speed is also 0.866c.
Third sentence:
Then, probe A flew out of the rocket as a result of the annihilation of 1 jar of fuel on board the rocket; and since probe A now has 4 times the mass and is flying in the same direction as the rocket, the speed of probe A relative to the platform is 0.9682c, so the Lorentz factor for probe A is 4, and therefore the kinetic energy of probe A is:
Ek = 1; * (4 – 1) = 3;
Addition to the third sentence:
The rest mass of probe A is 1 kg, and the rest mass of the fuel in the jar in the rocket is also 1 kg, so the total rest mass of this set is 1 kg + 1 kg = 2 kg.
When this set is moving relative to the platform at speed of 0.866c (while in the rocket), its mass is twice as large, and therefore the total energy of probe A is 2; and of fuel in the jar is also 2;.
When the fuel in the jar annihilates, this released energy is transformed into the kinetic energy of probe A.
As a result, the total energy of probe A is 2; + 2; = 4;, and therefore the mass of probe A is 4 times greater, so its speed relative to the platform is 0.9682c, because at this speed the mass of the body is 4 times greater.
This is the end of Kaziuk's Sequence, which I carried out in accordance with the law of conservation of energy.
Now I'll show what follows from special theory of relativity:
Well, Einstein's theory says that from the astronaut's point of view, the rocket is at rest and the platform is in motion.
And since probe B has speed of 0.866c relative to the platform, then under analogous circumstances, probe A has speed of 0.866c relative to the rocket.
And since the platform has speed of 0.866c relative to the rocket, probe A has speed of 0.9897c relative to the platform, which results from relativistic velocity-addition formula.
u' = (0.866 + 0.866) / (1 + 0.866 * 0.866 / 12) = 0.9897
So the Lorentz factor for probe A is about 7, and therefore the kinetic energy of probe A is:
Ek = 1; * (about 7 – 1) = about 6;
Now I'll demonstrate that any corrections to Kaziuk's Sequence taking into account physical phenomena have no effect on what it shows:
Let's consider a situation where, after the annihilation of 1 jar of fuel stored on the platform, the mass of probe B in motion doesn't increase by factor of 1 + 1 = 2, but by factor of 1 + 1 / 2 = 1.5.
In this situation, the Lorentz factor for probe B is 1.5, and its speed relative to the platform is 0.7453c.
Consequently, the rocket also has speed of 0.7453c, and probe A in the rocket has total energy of 1; [rest] + 0.5; [kinetic] = 1.5;, and the fuel in the jar in the rocket also has the same total energy of 1; [rest] + 0.5; [kinetic] = 1.5;.
After the fuel in the rocket annihilates and probe A leaves the rocket, the total energy of probe A is 1.5; [probe A's previous total energy] + (1 / 2); [half of the annihilated rest energy of the fuel] + 0.5; [kinetic energy of the fuel] = 2.5;.
So the Lorentz factor for probe A is 2.5, its speed relative to the platform is 0.9165c, and the kinetic energy of probe A is:
Ek = 1; * (2.5 – 1) = 1.5;
Now, what follows from special theory of relativity:
Since probe B has speed of 0.7453c relative to the platform, then probe A has the same speed relative to the rocket.
And if so, probe A has speed of 0.9583c relative to the platform.
So the Lorentz factor for probe A is 3.5.
Consequently, the kinetic energy of probe A is:
Ek = 1; * (3.5 – 1) = 2.5;
What this means:
For anyone with sublime mind – and only visitors from outer space have sublime minds – this means that Einstein's special theory of relativity has nothing to do with reality but is just a FALSE MATHEMATICAL TRICK, and this entire cosmology practiced by human professors of physics is a COSMIC BULLSHIT born from apish mind that human professors of physics inherited from their apish ancestors.
Unless Kaziuk's Sequence is wrong**, but that must be shown.
*The prize competition is open for everyone, but demonstration of anyone who isn't human professor of physics must be signed by some human professor of physics.
**The prize competition involves correcting Kaziuk's Sequence by such numerical values that its final result will be the same as what results from special theory of relativity.
Kaziuk von Märchendorf
mail: kaziukvonmaerchendorf@gmail.com
Facebook: Wszechświat według Kaziuka
What the Universe is REALLY like and how it REALLY works, I described in my book for visitors from outer space.
I posted the Introduction from my book here.
And here is my letter to human professors of physics in which I showed three times that human professors of physics have less brains than my she-goat.
(11 October 2024)
www.cosmocomp.com